In the figure,the current through the 3,Omega | vedclass

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(C) The $3\,\Omega$ and $6\,\Omega$ resistors are connected in parallel. Therefore,the potential difference across both is the same.Let $V_p$ be the p

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$4.8$

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(C) The $3\,\Omega$ and $6\,\Omega$ resistors are connected in parallel. Therefore,the potential difference across both is the same.Let $V_p$ be the potential difference across the parallel combination.$V_p = I_1 R_1 = I_2 R_2$$0.8 	imes 3 = I_2 	imes 6$$I_2 = \frac{2.4}{6} = 0.4\,A$The total current $I$ flowing through the $4\,\Omega$ resistor is the sum of the currents through the parallel branches:$I = I_1 + I_2 = 0.8\,A + 0.4\,A = 1.2\,A$The potential drop across the $4\,\Omega$ resistor is given by $V = I 	imes R = 1.2\,A 	imes 4\,\Omega = 4.8\,V$.

In the figure,the current through the $3\,\Omega$ resistor is $0.8\,A$. Then,the potential drop across the $4\,\Omega$ resistor is ........... $V$.

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