In the given circuit, the cells have zero int | vedclass

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(C) Let the potential at the junction between the two cells be $0 \ V$. Then the potential at the left terminal of the left cell is $-10 \ V$ and the

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$0.5, 0$

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(C) Let the potential at the junction between the two cells be $0 \ V$. Then the potential at the left terminal of the left cell is $-10 \ V$ and the potential at the right terminal of the right cell is $-10 \ V$. However, it is simpler to assign the potential at the top wire as $0 \ V$. Then the potential at the bottom wire (between the two cells) is $10 \ V$ relative to the left side and $10 \ V$ relative to the right side. For resistor $R_1$ $(20 \ \Omega)$: The potential difference across it is $10 \ V - 0 \ V = 10 \ V$. Thus, the current $I_1 = V/R_1 = 10 \ V / 20 \ \Omega = 0.5 \ A$. For resistor $R_2$ $(20 \ \Omega)$: The potential at the bottom right node is $10 \ V$ (due to the right cell). The potential at the top node is $10 \ V$ (due to the right cell). Thus, the potential difference across $R_2$ is $10 \ V - 10 \ V = 0 \ V$. Therefore, the current $I_2 = 0 \ A$. Hence, the currents are $0.5 \ A$ and $0 \ A$ respectively.

In the given circuit, the cells have zero internal resistance. The currents (in Amperes) passing through resistance $R_1$ and $R_2$ respectively, are

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