In the following circuit,the output Y becomes | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The circuit consists of an $AND$ gate followed by a $NAND$ gate. The inputs to the $AND$ gate are $A$ and $B$,so its output is $A \cdot B$.The inp

Vedclass · Accepted Answer

$A=1, B=1, C=0$

Vedclass · Answer

(D) The circuit consists of an $AND$ gate followed by a $NAND$ gate. The inputs to the $AND$ gate are $A$ and $B$,so its output is $A \cdot B$.The input $C$ passes through a $NOT$ gate,so its output is $\bar{C}$.These two signals are the inputs to the $NAND$ gate,which produces the final output $Y$.Thus,$Y = \overline{(A \cdot B) \cdot \bar{C}}$.Using De Morgan's law,$Y = \overline{A \cdot B} + \overline{\bar{C}} = \bar{A} + \bar{B} + C$.For the output $Y$ to be zero $(Y=0)$,we must have $\bar{A} + \bar{B} + C = 0$.This requires $\bar{A} = 0$,$\bar{B} = 0$,and $C = 0$ simultaneously.Therefore,$A = 1$,$B = 1$,and $C = 0$.

In the following circuit,the output $Y$ becomes zero for which of the following input combinations?

Similar Questions

Which logic gate is represented by the following diagram?

For the following combination of logic gates,when all the three inputs $A$,$B$ and $C$ are first 'high' and then 'low',the output $Y$ will be respectively.

In the given circuit,if $A=0, B=1$ and $C=1$ are inputs,then the values of $y_1$ and $y_2$ are respectively

The output $Y$ for the given inputs $A$ and $B$ to the circuit is:

Input waveforms $A$ and $B$ as shown in Fig-$I$ are applied to the combination of gates as shown in Fig-$II$. Which of the waveforms shown in Fig-$(i)$ to Fig-$(iv)$ correctly represents the output waveform $Y$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module