In the following combinations of logic gates, | vedclass

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(C) For output $A$: The inputs to the $NAND$ gate are $1$ and $1$,so its output is $0$. This $0$ passes through a $NOT$ gate,becoming $1$. The other i

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$1, 1, 0$

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(C) For output $A$: The inputs to the $NAND$ gate are $1$ and $1$,so its output is $0$. This $0$ passes through a $NOT$ gate,becoming $1$. The other input to the $OR$ gate comes from a $1$ passing through a $NOT$ gate,becoming $0$. Thus,the $OR$ gate receives inputs $1$ and $0$,resulting in output $A = 1$.For output $B$: The input $0$ passes through a $NOT$ gate to become $1$. The input $1$ passes through a $NOT$ gate to become $0$. These are inputs to a $NAND$ gate. Since $1$ and $0$ are inputs to $NAND$,the output is $1$. Thus,$B = 1$.For output $C$: The inputs to the $NOR$ gate are $1$ and $1$,so its output is $0$. The $AND$ gate receives this $0$ and the original input $1$. Since $0$ and $1$ are inputs to $AND$,the output is $0$. Thus,$C = 0$.Therefore,the outputs are $A = 1, B = 1, C = 0$.

In the following combinations of logic gates,the outputs $A, B$ and $C$ are respectively

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