The resultant gate and its Boolean expression | vedclass

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(A) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate.$1$. The output of the $NOR$ gate is $\overline{A+B}$.$2$. This output is then

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$OR$,$A+B$

Vedclass · Answer

(A) The given circuit consists of a $NOR$ gate followed by a $NOT$ gate.$1$. The output of the $NOR$ gate is $\overline{A+B}$.$2$. This output is then passed through a $NOT$ gate (inverter),which performs the complement operation.$3$. The final output $Y$ is the complement of the $NOR$ output: $Y = \overline{(\overline{A+B})} = A+B$.$4$. The Boolean expression $A+B$ corresponds to the $OR$ gate.Therefore,the combination of a $NOR$ gate and a $NOT$ gate acts as an $OR$ gate.

The resultant gate and its Boolean expression in the given circuit is

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