In the following combinations of logic gates, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For circuit $A$: The inputs to the $NAND$ gate are $1$ and $1$,so its output is $0$. This $0$ passes through a $NOT$ gate,becoming $1$. The $OR$ g

Vedclass · Accepted Answer

$1, 1, 0$

Vedclass · Answer

(A) For circuit $A$: The inputs to the $NAND$ gate are $1$ and $1$,so its output is $0$. This $0$ passes through a $NOT$ gate,becoming $1$. The $OR$ gate receives inputs $1$ and $0$,resulting in an output of $1$.For circuit $B$: The inputs $0$ and $1$ pass through $NOT$ gates,becoming $1$ and $0$ respectively. These are inputs to a $NAND$ gate. Since $1 	ext{ AND } 0 = 0$,the $NAND$ gate (which is $NOT$-$AND$) outputs $1$.For circuit $C$: The $OR$ gate receives inputs $1$ and $1$,resulting in an output of $1$. However,the diagram shows the $OR$ gate is followed by a $NOT$ bubble (making it a $NOR$ gate),so the output is $0$. This $0$ and the input $1$ are fed into an $AND$ gate,resulting in an output of $0$.Thus,the outputs are $1, 1, 0$ respectively.

In the following combinations of logic gates,the outputs of $A, B$ and $C$ are respectively

Similar Questions

For the circuit shown above,the equivalent $\text{GATE}$ is:

In the following combination of logic gates,the output $Y$ can be written in terms of inputs $A$ and $B$ as:

The Boolean equation for the circuit given in the figure is

The given truth table is correct for:
$P: 1, 1, 0, 0$
$Q: 1, 0, 1, 0$
$R: 1, 0, 0, 0$

In the circuit shown, inputs $A$ and $B$ are in states $1$ and $0$ respectively. What is the only possible stable state of the outputs $X$ and $Y$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module