In the following nuclear reactions _7N^{14} + | vedclass

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Question

(A) For the first reaction: $_7N^{14} + _2He^4 	o _8O^{17} + X_1$. Sum of atomic numbers: $7 + 2 = 8 + Z_1 \implies Z_1 = 1$. Sum of mass numbers: $1

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$_1H^1$ and $_0n^1$

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(A) For the first reaction: $_7N^{14} + _2He^4 	o _8O^{17} + X_1$. Sum of atomic numbers: $7 + 2 = 8 + Z_1 \implies Z_1 = 1$. Sum of mass numbers: $14 + 4 = 17 + A_1 \implies A_1 = 1$. Thus,$X_1$ is $_1H^1$ (a proton). For the second reaction: $_{13}Al^{27} + _1D^2 	o _{14}Si^{28} + X_2$. Sum of atomic numbers: $13 + 1 = 14 + Z_2 \implies Z_2 = 0$. Sum of mass numbers: $27 + 2 = 28 + A_2 \implies A_2 = 1$. Thus,$X_2$ is $_0n^1$ (a neutron). Therefore,$X_1$ and $X_2$ are $_1H^1$ and $_0n^1$ respectively.

In the following nuclear reactions $_7N^{14} + _2He^4 \to _8O^{17} + X_1$ and $_{13}Al^{27} + _1D^2 \to _{14}Si^{28} + X_2$,$X_1$ and $X_2$ are respectively:

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