In the nuclear reaction $_{12}Mg^{24} + _{2}He^{4} = _{0}n^{1} + ?$,the product nucleus is:

  • A
    $_{13}Al^{27}$
  • B
    $_{14}Si^{27}$
  • C
    $_{13}Al^{28}$
  • D
    $_{12}Mg^{25}$

Explore More

Similar Questions

The missing particle in the reaction,$_{92}^{235}U + _{0}^{1}n \to _{56}^{146}Ba + ... + 3_{0}^{1}n$ is

Difficult
View Solution

In the sequence of the following nuclear reactions $_{92}X^{238}$ $\xrightarrow{-\alpha} Y$ $\xrightarrow{-\beta} Z$ $\xrightarrow{-\beta} L$ $\xrightarrow{-n\alpha} _{84}M^{218}$. The value of $n$ will be:

Difficult
View Solution

The nuclear reaction $_{17}Cl^{37} + _1H^2 \to _{18}Ar^{38} + _0n^1$ represents:

According to the nuclear reaction $_4Be + _2He^4 \to _6C^{12} + _0n^1$,what is the mass number of the $Be$ atom?

In the following nuclear reactions $_7N^{14} + _2He^4 \to _8O^{17} + X_1$ and $_{13}Al^{27} + _1D^2 \to _{14}Si^{28} + X_2$,$X_1$ and $X_2$ are respectively:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo