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(A) The initial nucleus $D$ has mass number $A = 182$ and atomic number $Z = 74$.$1$. Alpha decay $(\alpha)$: Mass number decreases by $4$, atomic num

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$174$ and $71$

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(A) The initial nucleus $D$ has mass number $A = 182$ and atomic number $Z = 74$.$1$. Alpha decay $(\alpha)$: Mass number decreases by $4$, atomic number decreases by $2$.$2$. Beta decay $(\beta^-)$: Mass number remains unchanged, atomic number increases by $1$.$3$. Gamma decay $(\gamma)$: Mass number and atomic number remain unchanged.Calculation for mass number $(A)$:$A_{final} = 182 - 4 (	ext{first } \alpha) - 4 (	ext{second } \alpha) = 182 - 8 = 174$.Calculation for atomic number $(Z)$:$Z_{final} = 74 - 2 (	ext{first } \alpha) + 1 (\beta^-) - 2 (	ext{second } \alpha) = 74 - 4 + 1 = 71$.Thus, the mass number is $174$ and the atomic number is $71$.

In the following nuclear reaction,$D \xrightarrow{\alpha} D_{1} \xrightarrow{\beta^-} D_{2} \xrightarrow{\alpha} D_{3} \xrightarrow{\gamma} D_{4}$. The mass number of $D$ is $182$ and the atomic number is $74$. The mass number and atomic number of $D_{4}$ respectively will be:

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