In the following reaction sequence,Methylenec | vedclass

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(B) The reaction of $methylenecyclohexane$ with $B_2H_6$ followed by $H_2O_2/NaOH$ is a hydroboration-oxidation reaction,which follows anti-$Markownik

Vedclass · Accepted Answer

$X = 	ext{cyclohexylmethanol}, Y = 	ext{cyclohexanecarboxylic acid}$

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(B) The reaction of $methylenecyclohexane$ with $B_2H_6$ followed by $H_2O_2/NaOH$ is a hydroboration-oxidation reaction,which follows anti-$Markownikoff$ addition of water to the double bond. This results in the formation of a primary alcohol,$cyclohexylmethanol$ $(X)$.$CrO_3$ in the presence of $H_2SO_4$ is known as Jones reagent,which is a strong oxidizing agent. It oxidizes primary alcohols directly to carboxylic acids. Therefore,$cyclohexylmethanol$ is oxidized to $cyclohexanecarboxylic acid$ $(Y)$.

In the following reaction sequence,
$Methylenecyclohexane$ $\xrightarrow[(ii) H_2O_2/NaOH]{(i) B_2H_6} X$ $\xrightarrow{CrO_3/H_2SO_4} Y$
$X$ and $Y$ are:

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In the following reaction sequence,$Methylenecyclohexane$ $\xrightarrow[(ii) H_2O_2/NaOH]{(i) B_2H_6} X$ $\xrightarrow{CrO_3/H_2SO_4} Y$$X$ and $Y$ are: