In the following reaction sequence,Br-CH_2-CH | vedclass

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(A) $1$. The starting material $Br-CH_2-CH(Br)-Ph$ undergoes dehydrohalogenation with $Alc. KOH$ followed by $NaNH_2$ to form the alkyne $X$,which is

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$Ph-C \equiv C-H$ and $m-NO_2-C_6H_4-CO-CH_3$

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(A) $1$. The starting material $Br-CH_2-CH(Br)-Ph$ undergoes dehydrohalogenation with $Alc. KOH$ followed by $NaNH_2$ to form the alkyne $X$,which is phenylacetylene $(Ph-C \equiv C-H)$.$2$. The alkyne $X$ $(Ph-C \equiv C-H)$ undergoes acid-catalyzed hydration $(HgSO_4/dil. H_2SO_4, \Delta)$ to form an enol intermediate,which tautomerizes to acetophenone $(Ph-CO-CH_3)$.$3$. Acetophenone is then subjected to nitration using $Conc. HNO_3/H_2SO_4$. Since the acetyl group $(-CO-CH_3)$ is a meta-directing group,the nitro group $(-NO_2)$ is introduced at the meta-position,yielding $m-nitroacetophenone$ $(Y)$.

In the following reaction sequence,
$Br-CH_2-CH(Br)-Ph$ $\xrightarrow[2. NaNH_2]{1. Alc. KOH} X$ $\xrightarrow[4. Conc. HNO_3/H_2SO_4]{3. HgSO_4/dil. H_2SO_4, Heat} Y$
$X$ and $Y$ respectively are,

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In the following reaction sequence,$Br-CH_2-CH(Br)-Ph$ $\xrightarrow[2. NaNH_2]{1. Alc. KOH} X$ $\xrightarrow[4. Conc. HNO_3/H_2SO_4]{3. HgSO_4/dil. H_2SO_4, Heat} Y$$X$ and $Y$ respectively are,