(A) The reaction is $HNO_4 + H_2O \longrightarrow HNO_3 + H_2O_2$.In the product $HNO_3$ (Nitric acid),the oxidation state of $N$ is calculated as: $1

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If product is oxy acid with $-ic$ suffix

(A) The reaction is $HNO_4 + H_2O \longrightarrow HNO_3 + H_2O_2$.In the product $HNO_3$ (Nitric acid),the oxidation state of $N$ is calculated as: $1 + x + 3(-2) = 0 \implies x = +5$.The suffix $-ic$ is used for $HNO_3$ (Nitric acid) where the central atom is in its highest oxidation state.Therefore,the product $HNO_3$ is an oxyacid with an $-ic$ suffix.

Class 11 Chemistry Redox Reactions Oxidation number and Oxidation state

Difficult

In the following reaction,assign the oxidation state of the underlined atom for the product of complete hydrolysis at $R.T.$:
$H\underline{N}O_4 + H_2O \longrightarrow HNO_3 + H_2O_2$

A
If product is oxy acid with $-ic$ suffix
B
If product is oxy acid with $-ous$ suffix
C
If product are two oxy acids,one with $-ic$ suffix and other one with $-ous$ suffix
D
If product is not oxy acid,neither with $-ic$ suffix nor with $-ous$ suffix