In the following species, the one which is li | vedclass

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(C) The benzoin condensation involves the reaction of two molecules of benzaldehyde in the presence of a cyanide ion $(CN^-)$ catalyst to form benzoin

Vedclass · Accepted Answer

$Ph-C^-(OH)(CN)$

Vedclass · Answer

(C) The benzoin condensation involves the reaction of two molecules of benzaldehyde in the presence of a cyanide ion $(CN^-)$ catalyst to form benzoin. The mechanism begins with the nucleophilic attack of $CN^-$ on the carbonyl carbon of benzaldehyde. This is followed by a proton transfer (tautomerization) to form a carbanion intermediate, which is stabilized by the electron-withdrawing $CN$ group and the phenyl ring. The structure of this key intermediate is $Ph-C^-(OH)(CN)$. This carbanion then attacks another molecule of benzaldehyde to continue the reaction, eventually leading to the formation of benzoin after the elimination of the $CN^-$ catalyst.

In the following species, the one which is likely to be the intermediate during benzoin condensation of benzaldehyde is

Similar Questions

With a change in hybridisation of the carbon bearing the charge,the stability of a carbanion increases in the order:

For the following bond cleavages,use curved-arrows to show the electron flow and classify each as homolysis or heterolysis. Identify the reactive intermediate produced as free radical,carbocation,or carbanion.

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Which of the following is more stable than the remaining three?

Which of the following contains three pairs of electrons around the central carbon atom?

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