In the following unbalanced reaction,the prod | vedclass

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(A) Aluminium oxide $(Al_2O_3)$ is amphoteric in nature and reacts with an aqueous solution of sodium hydroxide $(NaOH)$ to form a soluble complex,sod

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$Na_3[Al(OH)_6]$

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(A) Aluminium oxide $(Al_2O_3)$ is amphoteric in nature and reacts with an aqueous solution of sodium hydroxide $(NaOH)$ to form a soluble complex,sodium hexahydroxyaluminate$(III)$.The balanced chemical equation is:$Al_2O_3 + 2NaOH + 3H_2O \longrightarrow 2Na[Al(OH)_4]$ or more commonly represented as $Al_2O_3 + 6NaOH + 3H_2O \longrightarrow 2Na_3[Al(OH)_6]$ depending on the concentration. In the context of the Bayer process,the product is $Na[Al(OH)_4]$. However,given the options provided,$Na_3[Al(OH)_6]$ is the standard complex representing the hexahydroxyaluminate ion.

In the following unbalanced reaction,the product formed is $Al_2O_3 + NaOH_{(aq)} + H_2O \longrightarrow$

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