In the formation of K_4[Fe(CN)_6],the hybridi | vedclass

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Question

(B) In $K_4[Fe(CN)_6]$,the central metal ion is $Fe^{2+}$.The atomic number of $Fe$ is $26$,so the electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6

Vedclass · Accepted Answer

$d^2sp^3$

Vedclass · Answer

(B) In $K_4[Fe(CN)_6]$,the central metal ion is $Fe^{2+}$.The atomic number of $Fe$ is $26$,so the electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.$CN^-$ is a strong field ligand,which causes pairing of electrons in the $3d$ orbitals.After pairing,two $3d$ orbitals become vacant.These two $3d$ orbitals,one $4s$ orbital,and three $4p$ orbitals undergo $d^2sp^3$ hybridisation to form six equivalent octahedral hybrid orbitals.Thus,the hybridisation involved is $d^2sp^3$.

List-$I$ (Complexes)	List-$II$ (Hybridisation)
$A$. $[Ni(CO)_4]$	$I$. $sp^3$
$B$. $[Cu(NH_3)_4]^{2+}$	$II$. $dsp^2$
$C$. $[Fe(NH_3)_6]^{2+}$	$III$. $sp^3d^2$
$D$. $[Fe(H_2O)_6]^{2+}$	$IV$. $d^2sp^3$

In the formation of $K_4[Fe(CN)_6]$,the hybridisation involved is

Similar Questions

Match List-$I$ with List-$II$:

List-$I$ (Complexes) List-$II$ (Hybridisation)

$A$. $[Ni(CO)_4]$ $I$. $sp^3$

$B$. $[Cu(NH_3)_4]^{2+}$ $II$. $dsp^2$

$C$. $[Fe(NH_3)_6]^{2+}$ $III$. $sp^3d^2$

$D$. $[Fe(H_2O)_6]^{2+}$ $IV$. $d^2sp^3$

Which of the following complexes has a square planar geometry?

Which of the following complexes involves $4p$ orbitals for hybridization?

Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour?

The spin-only magnetic moment of $[MnBr_4]^{2-}$ is $5.9 \ BM$. Predict the geometry of the complex ion.

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