In the formula bar{x} = A + frac{Sigma f_{i} | vedclass

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(A) The formula provided is for the step-deviation method to calculate the mean of grouped data.In this method,the deviation $d_{i}$ is defined as $d_

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$\frac{x_{i} - A}{c}$

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(A) The formula provided is for the step-deviation method to calculate the mean of grouped data.In this method,the deviation $d_{i}$ is defined as $d_{i} = x_{i} - A$,where $x_{i}$ is the class mark and $A$ is the assumed mean.The variable $u_{i}$ is defined as the ratio of the deviation to the class width $c$,which is given by $u_{i} = \frac{x_{i} - A}{c}$.Therefore,the correct expression for $u_{i}$ is $\frac{x_{i} - A}{c}$.

Class	$0-5$	$5-10$	$10-15$	$15-20$	$20-25$
Frequency	$10$	$15$	$12$	$20$	$9$

Class	$4-8$	$8-12$	$12-16$	$16-20$	$20-24$	$24-28$
Frequency	$9$	$8$	$12$	$7$	$15$	$1$

In the formula $\bar{x} = A + \frac{\Sigma f_{i} u_{i}}{\Sigma f_{i}} \times c$ for the mean,$u_{i} = \ldots \ldots \ldots$

Similar Questions

The formula to find the mean of an ungrouped data is ........

For the following distribution:

Class $0-5$ $5-10$ $10-15$ $15-20$ $20-25$

Frequency $10$ $15$ $12$ $20$ $9$

the sum of the lower limits of the median class and the modal class is:

The modal class of the following frequency distribution is ........
Class $4-8$ $8-12$ $12-16$ $16-20$ $20-24$ $24-28$
Frequency $9$ $8$ $12$ $7$ $15$ $1$

For a given frequency distribution,the total frequency is $25$ and $\Sigma f_{i} x_{i} = 120$. Then,the mean is $\ldots$

In the formula $\bar{x} = A + \frac{\Sigma f_{i} d_{i}}{\Sigma f_{i}}$,$d_{i} =$ .........

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