In the formula Z = l + left( frac{f_{1} - f_{ | vedclass

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(B) In the formula for the mode of grouped data,$Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} ight) 	imes c$,the variables are defin

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frequency of the modal class

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(B) In the formula for the mode of grouped data,$Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} ight) 	imes c$,the variables are defined as follows:$l$: lower limit of the modal class.$f_{1}$: frequency of the modal class.$f_{0}$: frequency of the class preceding the modal class.$f_{2}$: frequency of the class succeeding the modal class.$c$: size of the class interval.Therefore,$f_{1}$ represents the frequency of the modal class.

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$
Frequency	$2$	$4$	$10$	$20$	$18$	$20$	$16$	$10$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$
Frequency	$7$	$16$	$25$	$32$	$20$

In the formula $Z = l + \left( \frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}} \right) \times c$,$f_{1}$ represents:

Similar Questions

In the formula $M = l + \frac{(\frac{n}{2} - cf)}{f} \times h$ for the median,$f = \ldots \ldots \ldots$

Find the mean of the following frequency distribution:

Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$

Frequency $2$ $4$ $10$ $20$ $18$ $20$ $16$ $10$

In the usual notations,$Z - M = \ldots \ldots \ldots \quad (M - \bar{x})$

For a given frequency distribution,$A = 450, c = 100, \Sigma f_{i} u_{i} = -20$ and $\Sigma f_{i} = 20$. Then,the mean $\bar{x} = \ldots$

For the following data,the modal class is .... .
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$
Frequency $7$ $16$ $25$ $32$ $20$

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