In the given (V-T) diagram,what is the relati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to the ideal gas equation,$PV = nRT$,which can be rewritten as $V = (nR/P)T$.For an isobaric process,the pressure $P$ is constant,and $V

Vedclass · Accepted Answer

$P_2 < P_1$

Vedclass · Answer

(B) According to the ideal gas equation,$PV = nRT$,which can be rewritten as $V = (nR/P)T$.For an isobaric process,the pressure $P$ is constant,and $V \propto T$.Therefore,the $(V-T)$ graph is a straight line passing through the origin,where the slope of the line is given by $m = nR/P$.Since the slope $m$ is inversely proportional to the pressure $P$ $(m \propto 1/P)$,a larger slope corresponds to a smaller pressure.From the given diagram,the angle $	heta_2 > 	heta_1$,which implies that the slope of the line for $P_2$ is greater than the slope of the line for $P_1$ (i.e.,$	ext{slope}_2 > 	ext{slope}_1$).Since the slope is inversely proportional to pressure,we conclude that $P_2 < P_1$.

In the given $(V-T)$ diagram,what is the relation between pressure $P_1$ and $P_2$?

Similar Questions

If $A$ and $B$ are not disjoint sets,then $n(A \cup B) =$

Which of the following is not a polymer?

If $\frac{2 x^3+x^2-5}{x^4-25}=\frac{A x+B}{x^2-5}+\frac{C x+1}{x^2+5}$,then $(A, B, C)$ equals to

The equation of the circle which passes through the origin and cuts orthogonally each of the circles $x^2+y^2-6x+8=0$ and $x^2+y^2-2x-2y-7=0$ is

The wavelengths of two notes in air are $\frac{36}{195} ~m$ and $\frac{36}{193} ~m$. Each note produces $10$ beats per second separately with a third note of fixed frequency. The velocity of sound in air in $m/s$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module