In the given circuit, the current through the $5 \, mH$ inductor in steady state is

Two inductors of $60 mH$ each are joined in parallel. The current passing through this combination is $2.2 A$. The energy stored in this combination of inductors in joule is

Two coils of self-inductance $L_{1}$ and $L_{2}$ are connected in series. If the mutual inductance of the coils is $M$,the equivalent self-inductance of the combination shown in the figure will be:

An inductor coil of inductance $L$ is cut into two equal parts and both the parts are connected in parallel. The net inductance is

Two coils with self-inductance $1 H$ and $3 H$ are connected in series. Their mutual inductance is $5 H$. The equivalent self-inductance of the combination is: (in $H$)

Three coils of inductance $L_1 = 2 \ H$, $L_2 = 3 \ H$, and $L_3 = 6 \ H$ are connected such that they are separated from each other. To obtain an effective inductance of $1 \ H$, which of the following combinations, as shown in the figure, is correct?