In the given circuit, the potential difference across the plates of the capacitor $C$ in steady state is (in $V$)

The capacitor of capacitance $C$ in the circuit shown is fully charged initially. The resistance is $R$. After the switch $S$ is closed,the time taken to reduce the stored energy in the capacitor to half its initial value is

The circuit shown in the figure consists of a battery of $emf$ $\varepsilon = 10 \,V$,a capacitor of capacitance $C = 1.0 \, \mu F$,and three resistors of values $R_1 = 2 \, \Omega$,$R_2 = 2 \, \Omega$,and $R_3 = 1 \, \Omega$. Initially,the capacitor is completely uncharged and the switch $S$ is open. The switch $S$ is closed at $t = 0$.

The potential difference between the plates of a parallel plate capacitor is changing at the rate of $10^6\, V/s$. If the capacitance is $2\,\mu F$,the displacement current in the dielectric of the capacitor will be......$A$

The capacitor $C$ is initially without charge. $X$ is now joined to $Y$ for a long time,during which $H_1$ heat is produced in the resistance $R$. The $X-Y$ connection is removed and $X$ is now joined to $Z$ for a long time,during which heat $H_2$ is produced in $R$.

At time $t = 0$,the switch $K$ is closed. Which of the following statements is true for the current '$i$' flowing through the resistor $AB$ in the given circuit?