The capacitor of capacitance $C$ in the circuit shown is fully charged initially. The resistance is $R$. After the switch $S$ is closed,the time taken to reduce the stored energy in the capacitor to half its initial value is

$A$ capacitor is charged to $320\ V$ and then connected to a resistor. After $1\ s$,the voltage is $240\ V$. What will be the voltage after $2\ s$ and $3\ s$?

In the circuit shown,the cells are ideal and of equal emfs $E$. The capacitance of the capacitor is $C$ and the resistance of the resistor is $R$. $X$ is first joined to $Y$ and then to $Z$. After a long time,the total heat produced in the resistor will be:

$A$ filter circuit used in a rectifier has a load resistance of $200 \Omega$ and a capacitance of $15 \mu\text{F}$. The value of the time constant is . . . . . . .

Let $C$ be the capacitance of a capacitor discharging through a resistor $R$. Suppose $t_{1}$ is the time taken for the energy stored in the capacitor to reduce to half its initial value and $t_{2}$ is the time taken for the charge to reduce to one-fourth its initial value. Then the ratio $t_{1} / t_{2}$ will be

In the circuit shown in the diagram,the capacitances of the capacitors $C_1$,$C_2$,and $C_3$ are $4\ \mu F$,$6\ \mu F$,and $12\ \mu F$ respectively. The switch $S$ remains closed for a long time. When the switch $S$ is opened,which of the following statements will be correct about the current flowing through the battery $B$?