In the given circuit,the value of current $I_{L}$ will be in $mA$. (When $R_{L} = 1 \, k\Omega$)

$A$ Zener diode,having a breakdown voltage equal to $15\,V$,is used in a voltage regulator circuit as shown in the figure. The current through the diode is......$mA$.

Zener breakdown in a semiconductor diode occurs when

Two Zener diodes ($A$ and $B$) having breakdown voltages of $6\, V$ and $4\, V$ respectively,are connected as shown in the circuit below. The output voltage $V_{0}$ variation with input voltage linearly increasing with time,is given by: $(V_{\text{input}} = 0\, V$ at $t = 0)$ (figures are qualitative).

$A$ Zener diode of breakdown voltage $V_{Z} = 8\,V$ and maximum Zener current $I_{ZM} = 10\,mA$ is subjected to an input voltage $V_{i} = 10\,V$ with a series resistance $R = 100\,\Omega$. In the given circuit,$R_{L}$ represents the variable load resistance. The ratio of the maximum and minimum value of $R_{L}$ is

In the given circuit,the value of $I_{L}$ (in $mA$) will be: (in $.5$)