In the given transistor circuit,the base curr | vedclass

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(B) From the circuit diagram,the base-emitter junction is connected to a $7 \, V$ source through the resistor $R_b$.Assuming the potential drop across

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$200$

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(B) From the circuit diagram,the base-emitter junction is connected to a $7 \, V$ source through the resistor $R_b$.Assuming the potential drop across the forward-biased base-emitter junction is negligible $(V_{be} \approx 0 \, V)$,the entire voltage of the source appears across the resistor $R_b$.Given: $V = 7 \, V$ and $I_b = 35 \, \mu A = 35 	imes 10^{-6} \, A$.Using Ohm's law,$V = I_b 	imes R_b$.$R_b = \frac{V}{I_b} = \frac{7 \, V}{35 	imes 10^{-6} \, A}$.$R_b = \frac{1}{5} 	imes 10^6 \, \Omega = 0.2 	imes 10^6 \, \Omega = 200 	imes 10^3 \, \Omega$.Therefore,$R_b = 200 \, k\Omega$.

In the given transistor circuit,the base current is $35 \mu A$. The value of $R_b$ is.....$k\Omega$.

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