(A) In the molecule $CH \equiv C - CH = CH_2$,we can label the carbon atoms as follows:$C^1H \equiv C^2 - C^3H = C^4H_2$The $C^2$ atom is attached to

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(A) In the molecule $CH \equiv C - CH = CH_2$,we can label the carbon atoms as follows:$C^1H \equiv C^2 - C^3H = C^4H_2$The $C^2$ atom is attached to a triple bond,so it is $sp$ hybridized.The $C^3$ atom is attached to a double bond,so it is $sp^2$ hybridized.Therefore,the $C^2 - C^3$ single bond is formed by the overlap of an $sp$ orbital and an $sp^2$ orbital,resulting in $sp - sp^2$ hybridization.

Class 11 Chemistry 8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds Bonding and hybridisation in organic compounds

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In the molecule $CH \equiv C - CH = CH_2$,the hybridisation of the $C - C$ single bond is:

A
$sp - sp^2$
B
$sp^3 - sp^3$
C
$sp^2 - sp^2$
D
$sp^3 - sp$

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8-1.Organic Chemistry : Classification and Nomenclature of Organic compounds

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Bonding and hybridisation in organic compounds

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The hybridisation of each carbon in the following compound respectively is:
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The enolic form of acetone contains

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The base strength order of $H_3C-CH_2^-$ $(i)$,$H_2C=CH^-$ $(ii)$,and $HC \equiv C^-$ $(iii)$ is:

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In the molecule $CH \equiv C - CH = CH_2$,the hybridisation of the $C - C$ single bond is:

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The bond between carbon atom $(1)$ and carbon atom $(2)$ in compound $N \equiv C - CH = CH_2$ involves the hybridised carbon as

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The hybridisation of each carbon in the following compound respectively is:
$CH_3-C(=O)-CH_2-CN$