In the nuclear reaction ${ }_{7}^{14} N + X \rightarrow { }_{6}^{14} C + { }_{1}^{1} H$, the $X$ will be

  • A
    ${ }_{-1}^{0} e$
  • B
    ${ }_{1}^{1} H$
  • C
    ${ }_{1}^{2} H$
  • D
    ${ }_{0}^{1} n$

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