In the prime factorization of $37! = 2^{\alpha_2} \cdot 3^{\alpha_3} \cdot 5^{\alpha_5} \cdots 37^{\alpha_{37}}$,the ratio $\alpha_3 : \alpha_5$ is:

  • A
    $3 : 5$
  • B
    $17 : 8$
  • C
    $5 : 3$
  • D
    $8 : 21$

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