In the reaction Me-C equiv C-Et xrightarrow{N | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. The reduction of $Me-C \equiv C-Et$ with $Na/liq. NH_3$ (Birch reduction/dissolving metal reduction) yields the trans-alkene,$trans-pent-2-en

Vedclass · Accepted Answer

$A$ binary mixture which is optically inactive due to external compensation

Vedclass · Answer

(B) $1$. The reduction of $Me-C \equiv C-Et$ with $Na/liq. NH_3$ (Birch reduction/dissolving metal reduction) yields the trans-alkene,$trans-pent-2-ene$ $(P)$.$2$. The subsequent reaction of $trans-pent-2-ene$ with $Br_2$ in $CCl_4$ proceeds via anti-addition.$3$. Anti-addition of $Br_2$ to a trans-alkene results in the formation of a pair of enantiomers,which constitutes a racemic mixture.$4$. $A$ racemic mixture is optically inactive due to external compensation,as the optical rotation of one enantiomer is cancelled by the equal and opposite rotation of the other.

In the reaction $Me-C \equiv C-Et$ $\xrightarrow{Na/liq. NH_3} P$ $\xrightarrow[CCl_4]{Br_2} (Q)$; then $Q$ is

Similar Questions

Acetone is formed by the ozonolysis of which of the following?

Which of the following acids adds to propene in the presence of peroxide to give anti-Markownikoff's product?

Which one of the following organic compounds decolourizes an alkaline $KMnO_4$ solution?

$But-1-ene \xrightarrow[(ii) NaBH_4]{(i) (CH_3COO)_2Hg/H_2O} ?$
The product in the above reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module