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(D) The reaction of but$-2-$ene with $H_3O^{+}$ involves the formation of a planar carbocation intermediate,$CH_3-CH_2-C^{+}H-CH_3$. Since the carboca

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a racemic mixture

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(D) The reaction of but$-2-$ene with $H_3O^{+}$ involves the formation of a planar carbocation intermediate,$CH_3-CH_2-C^{+}H-CH_3$. Since the carbocation is planar,the nucleophile $(H_2O)$ can attack from either side of the plane with equal probability. This results in the formation of a $50:50$ mixture of $(R)$ and $(S)$ enantiomers of butan$-2-$ol,which is a racemic mixture.

In the reaction given below,the product would be: $CH_3-CH=CH-CH_3 \xrightarrow{H_3O^{+}} CH_3-CH_2-CH(OH)-CH_3$

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