In the reaction given below,what are the geom | vedclass

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(C) The reaction is $BCl_3 + NH_3 \rightarrow BCl_3 \cdot NH_3$ (where $X = BCl_3 \cdot NH_3$).In $BCl_3$,the boron atom is $sp^2$ hybridized with thr

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Trigonal planar,tetrahedral

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(C) The reaction is $BCl_3 + NH_3 \rightarrow BCl_3 \cdot NH_3$ (where $X = BCl_3 \cdot NH_3$).In $BCl_3$,the boron atom is $sp^2$ hybridized with three bond pairs and no lone pairs,resulting in a trigonal planar geometry.In the adduct $X$ $(BCl_3 \cdot NH_3)$,the boron atom undergoes a change in hybridization from $sp^2$ to $sp^3$ as it accepts a lone pair from the nitrogen atom of $NH_3$.Consequently,the boron atom in $X$ adopts a tetrahedral geometry.

List-$I$	List-$II$
$A$. $BF_3$	$II$. Trigonal planar
$B$. $ClF_3$	$III$. $T$-shape
$C$. $NH_3$	$IV$. Trigonal pyramidal
$D$. $NH_4^+$	$I$. Tetrahedral

In the reaction given below,what are the geometries of $BCl_3$ and $X$ respectively?
$BCl_3 + NH_3 \rightarrow X$

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In the reaction given below,what are the geometries of $BCl_3$ and $X$ respectively?$BCl_3 + NH_3 \rightarrow X$