In the reaction sequence:text{Ethanol} xright | vedclass

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(D) The reaction sequence is as follows:$1$. $	ext{Ethanol} (CH_3 CH_2 OH)$ reacts with $PCl_5$ to form $X$,which is chloroethane $(CH_3 CH_2 Cl)$.$2

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$CH_3 CH_2 OH$

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(D) The reaction sequence is as follows:$1$. $	ext{Ethanol} (CH_3 CH_2 OH)$ reacts with $PCl_5$ to form $X$,which is chloroethane $(CH_3 CH_2 Cl)$.$2$. Chloroethane $(CH_3 CH_2 Cl)$ reacts with alcoholic $KOH$ (dehydrohalogenation) to form $Y$,which is ethene $(CH_2 = CH_2)$.$3$. Ethene $(CH_2 = CH_2)$ reacts with $H_2SO_4$ at room temperature followed by hydrolysis $(H_2O, \Delta)$ to form $Z$,which is ethanol $(CH_3 CH_2 OH)$.Therefore,the product $Z$ is $CH_3 CH_2 OH$.

In the reaction sequence:
$\text{Ethanol}$ $\xrightarrow{PCl_5} X$ $\xrightarrow{\text{alc. } KOH} Y$ $\xrightarrow[H_2O, \Delta]{H_2SO_4, \text{room temp.}} Z$
The product $Z$ is:

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In the reaction sequence:$\text{Ethanol}$ $\xrightarrow{PCl_5} X$ $\xrightarrow{\text{alc. } KOH} Y$ $\xrightarrow[H_2O, \Delta]{H_2SO_4, \text{room temp.}} Z$The product $Z$ is: