In the reaction with HCl,an alkene reacts in | vedclass

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(C) According to Markovnikov's rule,the electrophile $(H^+)$ adds to the carbon with more hydrogen atoms,and the nucleophile $(Cl^-)$ adds to the more

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$C$. $A$ and $B$

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(C) According to Markovnikov's rule,the electrophile $(H^+)$ adds to the carbon with more hydrogen atoms,and the nucleophile $(Cl^-)$ adds to the more substituted carbon.$1-$Methylcyclohexene reacts with $HCl$ to form a tertiary carbocation at the $C1$ position,which then reacts with $Cl^-$ to give $1-$chloro$-1-$methylcyclohexane.$3-$Methylcyclohexene reacts with $HCl$ to form a secondary carbocation at the $C3$ position,which can undergo a $1,2-$hydride shift to form a more stable tertiary carbocation at the $C1$ position,eventually yielding $1-$chloro$-1-$methylcyclohexane.Methylenecyclohexane reacts with $HCl$ to form a tertiary carbocation at the $C1$ position,which then reacts with $Cl^-$ to give $1-$chloro$-1-$methylcyclohexane.Since all three alkenes can lead to the formation of $1-$chloro$-1-$methylcyclohexane,the question implies identifying which of the given options are valid. Given the options,$1-$methylcyclohexene,$3-$methylcyclohexene,and methylenecyclohexane all produce the same product. However,if the question asks for the most direct route,$1-$methylcyclohexene and methylenecyclohexane are primary candidates. Based on standard chemistry problems of this type,all listed alkenes can yield the product.

In the reaction with $HCl$,an alkene reacts in accordance with Markovnikov's rule to give the product $1-$chloro$-1-$methylcyclohexane. The possible alkene is:

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