In the reduction of nitrobenzene,which of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reduction of nitrobenzene $(C_6H_5NO_2)$ proceeds through several intermediates depending on the reaction conditions.Nitrobenzene is first red

Vedclass · Accepted Answer

$C_6H_5N=O$

Vedclass · Answer

(A) The reduction of nitrobenzene $(C_6H_5NO_2)$ proceeds through several intermediates depending on the reaction conditions.Nitrobenzene is first reduced to nitrosobenzene $(C_6H_5NO)$,which is an intermediate.Nitrosobenzene is then further reduced to $N$-phenylhydroxylamine $(C_6H_5NHOH)$.Among the given options,$C_6H_5N=O$ (nitrosobenzene) is a known intermediate in the reduction process.Therefore,the correct option is $A$.

In the reduction of nitrobenzene,which of the following is an intermediate?

Similar Questions

The most reactive amine towards dil. $HCl$ is . . . . . . .

The product formed from the following reaction sequence is:

Aniline in a set of reactions yielded a product $D$. The structure of product $D$ would be:
Aniline $\xrightarrow{NaNO_2/HCl} A$ $\xrightarrow{CuCN} B$ $\xrightarrow{H_2/Ni} C$ $\xrightarrow{HNO_2} D$

What is the correct order of basicity for the given amines in a chlorobenzene medium?
$(A)$ $CH_3CH_2NH_2$
$(B)$ Cyclohexylamine
$(C)$ $N$-Methylpiperidine
$(D)$ Pyrrolidine

The product formed when aniline is treated with chloroform in the presence of $KOH$ (alcoholic) is

Vedclass Test Series

Exam Paper Generator

Online Exam Module