In the sequence of the following reactions,X | vedclass

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Question

(A) $1$. The reaction sequence starts with methanol $(CH_3OH)$,which reacts with $HI$ to form methyl iodide $(CH_3I)$.$2$. $CH_3I$ reacts with $KCN$ t

Vedclass · Accepted Answer

$CH_3CH_2NH_2$ and $CH_3CH_2OH$

Vedclass · Answer

(A) $1$. The reaction sequence starts with methanol $(CH_3OH)$,which reacts with $HI$ to form methyl iodide $(CH_3I)$.$2$. $CH_3I$ reacts with $KCN$ to form methyl cyanide $(CH_3CN)$.$3$. Reduction of methyl cyanide $(CH_3CN)$ using a reducing agent (like $LiAlH_4$ or $H_2/Ni$) yields ethylamine $(CH_3CH_2NH_2)$,which is $X$.$4$. Ethylamine $(CH_3CH_2NH_2)$ reacts with nitrous acid $(HNO_2)$ to form ethyl alcohol $(CH_3CH_2OH)$,which is $Y$.

In the sequence of the following reactions,$X$ and $Y$ are respectively: $CH_3OH$ $\xrightarrow{HI} CH_3I$ $\xrightarrow{KCN} CH_3CN$ $\xrightarrow{\text{reduction}} X$ $\xrightarrow{HNO_2} Y$

Similar Questions

The major product $(R)$ of the following reaction is:
$C_6H_5NH_2$ $\xrightarrow[{0 \, ^\circ C}]{{HNO_2}} P$ $\xrightarrow{{HBF_4}} Q$ $\xrightarrow[{Cu, \, \Delta }]{{NaNO_2}} R$

The correct structures of $A$ and $B$ formed in the following reactions are:

Assertion $(A)$: $-NH_2$ group of aniline is ortho,para directing in electrophilic substitutions.
Reason $(R)$: $-NH_2$ group stabilises the arenium ion formed by the ortho,para attack of the electrophile.
The correct answer is

Which of the following will not give a primary amine upon reduction with $LiAlH_4$?

Which of the following compounds does not give alcohol on reduction?

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