In the series 7, 14, 28, ldots,what will be t | vedclass

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(D) The given series is $7, 14, 28, \ldots$.Observing the pattern: $14/7 = 2$,$28/14 = 2$.Since the ratio between consecutive terms is constant,this i

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$3584$

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(D) The given series is $7, 14, 28, \ldots$.Observing the pattern: $14/7 = 2$,$28/14 = 2$.Since the ratio between consecutive terms is constant,this is a Geometric Progression $(G.P.)$.Here,the first term $a = 7$ and the common ratio $r = 2$.The formula for the $n^{th}$ term of a $G.P.$ is $T_n = a 	imes r^{(n-1)}$.For the $10^{th}$ term $(n = 10)$:$T_{10} = 7 	imes 2^{(10-1)} = 7 	imes 2^9$.Since $2^9 = 512$,we have $T_{10} = 7 	imes 512 = 3584$.

In the series $7, 14, 28, \ldots$,what will be the $10^{th}$ term?

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In the series $7, 14, 28, \ldots$,what will be the $10^{th}$ term?

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