In the shown $AC$ circuit,the phase difference between currents $I_1$ and $I_2$ is:

  • A
    $\frac{\pi}{2} - \tan^{-1} \left( \frac{X_L}{R} \right)$
  • B
    $\tan^{-1} \left( \frac{X_L - X_C}{R} \right)$
  • C
    $\frac{\pi}{2} + \tan^{-1} \left( \frac{X_L}{R} \right)$
  • D
    $\tan^{-1} \left( \frac{X_L - X_C}{R} \right) + \frac{\pi}{2}$

Explore More

Similar Questions

Match List-$I$ with List-$II$ and choose the correct answer from the options given below:
List-$I$List-$II$
$A$. Purely capacitive circuit$I$. $I$ leads $V$ by $90^{\circ}$
$B$. Purely inductive circuit$II$. $I$ and $V$ are in phase
$C$. $LCR$ series at resonance$III$. $V$ leads $I$ by angle $\theta$
$D$. $LCR$ series circuit$IV$. $V$ leads $I$ by $90^{\circ}$

$A$ resistor $R=300 \Omega$ and a capacitor $C=25 \mu F$ are connected in series with a $50 \ V, \frac{50}{\pi} \ Hz$ $AC$ source. The average power dissipated in the circuit is (in $W$)

In the circuit shown in the figure,the $ac$ source gives a voltage $V = 20\cos(2000t)$. Neglecting source resistance,the voltmeter and ammeter readings will be:

Difficult
View Solution

An electrical device draws $2 \, kW$ power from $AC$ mains $(V_{rms} = 223 \, V = \sqrt{50000} \, V)$. The current lags in phase by $\tan \phi = -\frac{3}{4}$ compared to the voltage. Find $(i)$ $R$,$(ii)$ $X_C - X_L$,and $(iii)$ $I_M$. Another device has twice the values for $R$,$X_C$,and $X_L$. How are the answers affected?

If $L$,$C$,and $R$ are the self-inductance,capacitance,and resistance respectively,which of the following does not have the dimension of time?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo