In the Young's double slit experiment with so | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The condition for the $n^{th}$ maximum in a Young's double slit experiment is given by $d \sin 	heta = n \lambda$,where $d$ is the slit separatio

Vedclass · Accepted Answer

$\sin^{-1}(3 	imes 10^{-6})$

Vedclass · Answer

(D) The condition for the $n^{th}$ maximum in a Young's double slit experiment is given by $d \sin 	heta = n \lambda$,where $d$ is the slit separation,$	heta$ is the angular position,$n$ is the order of the maximum,and $\lambda$ is the wavelength of light.Given: $d = 0.589 \ m$,$\lambda = 589 \ nm = 589 	imes 10^{-9} \ m$,and $n = 3$.Substituting these values into the formula: $\sin 	heta = \frac{n \lambda}{d} = \frac{3 	imes 589 	imes 10^{-9}}{0.589}$.Since $0.589 = 589 	imes 10^{-3}$,we have $\sin 	heta = \frac{3 	imes 589 	imes 10^{-9}}{589 	imes 10^{-3}} = 3 	imes 10^{-6}$.Therefore,the angular position is $	heta = \sin^{-1}(3 	imes 10^{-6})$.

In the Young's double slit experiment with sodium light,the slits are $0.589 \ m$ apart. The angular separation of the third maximum from the central maximum will be (given $\lambda = 589 \ nm$):

Similar Questions

In Young's double-slit experiment,the width of one slit is twice that of the other. What is the ratio of the maximum to the minimum intensity?

In Young's experiment, the intensity ratio of the maxima and minima in an interference pattern produced by two coherent sources is $36 : 1$. The ratio of the amplitudes of the two individual sources will be

In Young's double-slit interference experiment,the ratio of the slit widths is $1:25$. Find the ratio of the maximum to minimum intensity in the interference pattern.

In Young's double slit experiment,the distance between the slits is reduced to half and the distance between the slit and the screen is doubled,then the fringe width:

If the screen is moved away from the plane of the slits in a Young's double slit experiment,then the

Vedclass Test Series

Exam Paper Generator

Online Exam Module