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(B) The impulse $I$ is equal to the change in momentum $\Delta P$.Given: mass $m = 5 \; kg$,initial velocity $u = 25 \; ms^{-1}$,final velocity $v = 0

Vedclass · Accepted Answer

Impulse will be same for both the cases but the average force will be different.

Vedclass · Answer

(B) The impulse $I$ is equal to the change in momentum $\Delta P$.Given: mass $m = 5 \; kg$,initial velocity $u = 25 \; ms^{-1}$,final velocity $v = 0 \; ms^{-1}$.Change in momentum $\Delta P = m(v - u) = 5(0 - 25) = -125 \; kg \cdot ms^{-1}$.Since the change in momentum is the same in both cases,the impulse $I = |\Delta P| = 125 \; N \cdot s$ is the same for both cases.The average force is given by $F_{	ext{avg}} = \frac{\Delta P}{\Delta t}$.For case $(i)$,$\Delta t_1 = 3 \; s$,so $F_{	ext{avg}, 1} = \frac{125}{3} \approx 41.67 \; N$.For case $(ii)$,$\Delta t_2 = 5 \; s$,so $F_{	ext{avg}, 2} = \frac{125}{5} = 25 \; N$.Since $\Delta t_1 
eq \Delta t_2$,the average forces are different. Thus,impulse is the same,but the average force is different.

In two different experiments,an object of mass $5 \; kg$ moving with a speed of $25 \; ms^{-1}$ hits two different walls and comes to rest within
$(i)$ $3 \; s$,$(ii)$ $5 \; s$,respectively.
Choose the correct option out of the following:

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In two different experiments,an object of mass $5 \; kg$ moving with a speed of $25 \; ms^{-1}$ hits two different walls and comes to rest within$(i)$ $3 \; s$,$(ii)$ $5 \; s$,respectively.Choose the correct option out of the following: