In which of the following reactions is phenol or sodium phenoxide $NOT$ formed?

  • A
    $C_6H_5N_2Cl + \text{alc. } KOH \to$
  • B
    $C_6H_5OCl + NaOH \to$
  • C
    $C_6H_5N_2Cl + \text{aq. } NaOH \to$
  • D
    $C_6H_5N_2Cl \xrightarrow[\Delta]{H_2O}$

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Major product of the reaction is

In the given reaction sequence,identify the correct reagents to prepare $A$ from $B$. The starting material is benzenesulfonic acid. The reaction with $\Delta / H_3O^+$ yields $B$ (benzene),and the reaction with $1. \text{Fused } NaOH, 2. H^+$ yields $A$ (phenol). Therefore,to prepare $A$ (phenol) from $B$ (benzene),the correct sequence of reagents is:

Given below are two statements:
Statement $I$: $p$-nitrophenol is more acidic than $m$-nitrophenol and $o$-nitrophenol.
Statement $II$: Ethanol will give immediate turbidity with Lucas reagent.
In the light of the above statements,choose the correct answer from the options given below:

For the given reaction,the value of $x$ is:

Match the items given in column $-I$ with the items given in column $-II$.
column $-I$ column $-II$
$(A)$ Antifreeze used in car engine $(1)$ Neutral $FeCl_3$
$(B)$ Solvent used in perfumes $(2)$ Glycerol
$(C)$ Starting material for picric acid $(3)$ Methanol
$(D)$ Wood spirit $(4)$ Phenol
$(E)$ Reagent used for detection of phenolic group $(5)$ Ethylene glycol
$(F)$ By-product of soap industry used in cosmetics $(6)$ Ethanol

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