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(A) For $C_2^+ 	o C_2$:$C_2^+$ has $9$ electrons,configuration: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p^1$. Bond order = $(6-

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$C_2^+ 	o C_2$

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(A) For $C_2^+ 	o C_2$:$C_2^+$ has $9$ electrons,configuration: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p^1$. Bond order = $(6-4)/2 = 1.0$. It is paramagnetic.$C_2$ has $12$ electrons,configuration: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p^4$. Bond order = $(8-4)/2 = 2.0$. It is diamagnetic.Since the bond order increased $(1.0 	o 2.0)$ and magnetic behavior changed (paramagnetic to diamagnetic),this is the correct transformation.

In which of the following transformations,the bond order has increased and the magnetic behaviour has changed?

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