In Young's double slit experiment,if the dist | vedclass

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(B) The formula for fringe width in Young's double slit experiment is given by $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of ligh

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(B) The formula for fringe width in Young's double slit experiment is given by $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the slits and the screen,and $d$ is the distance between the two slits.From the formula,it is clear that the fringe width $\beta$ is inversely proportional to the slit separation $d$,i.e.,$\beta \propto \frac{1}{d}$.If the distance between the slits is made half,i.e.,$d' = \frac{d}{2}$,then the new fringe width $\beta'$ will be:$\beta' = \frac{\lambda D}{d'} = \frac{\lambda D}{d/2} = 2 	imes \frac{\lambda D}{d} = 2\beta$.Therefore,the fringe width becomes double.

In Young's double slit experiment,if the distance between the two slits is halved,then the fringe width will become

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