In Young's double slit experiment,the intensi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given that the intensity of the first slit $I_1 = 2I_2$,where $I_2$ is the intensity of the second slit.The ratio of maximum intensity to minimum

Vedclass · Accepted Answer

$34$

Vedclass · Answer

(A) Given that the intensity of the first slit $I_1 = 2I_2$,where $I_2$ is the intensity of the second slit.The ratio of maximum intensity to minimum intensity in an interference pattern is given by the formula:$\frac{I_{\max}}{I_{\min}} = \left( \frac{\sqrt{I_1} + \sqrt{I_2}}{\sqrt{I_1} - \sqrt{I_2}} \right)^2$Substituting $I_1 = 2I_2$ into the formula:$\frac{I_{\max}}{I_{\min}} = \left( \frac{\sqrt{2I_2} + \sqrt{I_2}}{\sqrt{2I_2} - \sqrt{I_2}} \right)^2 = \left( \frac{\sqrt{2} + 1}{\sqrt{2} - 1} \right)^2$Rationalizing the denominator:$\frac{I_{\max}}{I_{\min}} = \left( \frac{(\sqrt{2} + 1)(\sqrt{2} + 1)}{(\sqrt{2} - 1)(\sqrt{2} + 1)} \right)^2 = (\sqrt{2} + 1)^4 = (2 + 1 + 2\sqrt{2})^2 = (3 + 2\sqrt{2})^2$Calculating the value:$\frac{I_{\max}}{I_{\min}} = 9 + 8 + 12\sqrt{2} = 17 + 12(1.414) \approx 17 + 16.968 \approx 33.968 \approx 34$.

In Young's double slit experiment,the intensity of light coming from the first slit is double the intensity from the second slit. The ratio of the maximum intensity to the minimum intensity on the interference fringe pattern observed is

Similar Questions

The ratio of intensities of two coherent sources is $p$. The visibility of the fringes in the interference pattern is given by:

In Young's double slit experiment,if the maximum intensity is $I$,then the angular position where the intensity becomes $\frac{I}{4}$ is:

The ratio of intensities of two waves is $9 : 1$. They are producing interference. The ratio of maximum and minimum intensities will be

Obtain the formula for the intensity of light if the phase difference at a point from two coherent sources is $\phi$.

In Young's double-slit experiment,the intensity at a point where the path difference is $\lambda$ is $k$. What will be the intensity at a point where the path difference is $\lambda/4$? ($\lambda$ = wavelength of light)

Vedclass Test Series

Exam Paper Generator

Online Exam Module