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(C) Given the ratio of intensities of two waves is $\frac{I_1}{I_2} = \frac{9}{1}$.Let the amplitudes of the two waves be $A_1$ and $A_2$. Since inten

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$4:1$

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(C) Given the ratio of intensities of two waves is $\frac{I_1}{I_2} = \frac{9}{1}$.Let the amplitudes of the two waves be $A_1$ and $A_2$. Since intensity $I \propto A^2$,the ratio of amplitudes is $\frac{A_1}{A_2} = \sqrt{\frac{I_1}{I_2}} = \sqrt{\frac{9}{1}} = \frac{3}{1}$.The ratio of maximum to minimum intensity is given by the formula:$\frac{I_{\max}}{I_{\min}} = \left( \frac{A_1 + A_2}{A_1 - A_2} \right)^2$.Substituting the values:$\frac{I_{\max}}{I_{\min}} = \left( \frac{3 + 1}{3 - 1} \right)^2 = \left( \frac{4}{2} \right)^2 = (2)^2 = \frac{4}{1}$.Thus,the ratio is $4:1$.

The ratio of intensities of two waves is $9 : 1$. They are producing interference. The ratio of maximum and minimum intensities will be

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