The initial EMF of the concentration cell sho | vedclass

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(B) This is a concentration cell where the same electrode $M(s)|M^+(aq)$ is used in both half-cells.For a concentration cell,the standard cell potenti

Vedclass · Accepted Answer

$0.059$

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(B) This is a concentration cell where the same electrode $M(s)|M^+(aq)$ is used in both half-cells.For a concentration cell,the standard cell potential $E^0_{cell} = 0 \ V$.The cell reaction is: $M(s) + M^+(0.1 \ M) ightarrow M^+(0.01 \ M) + M(s)$.Using the Nernst equation at $298 \ K$:$E_{cell} = E^0_{cell} - \frac{0.0591}{n} \log \frac{[M^+]_{anode}}{[M^+]_{cathode}}$Here,$n = 1$,$[M^+]_{anode} = 0.01 \ M$,and $[M^+]_{cathode} = 0.1 \ M$.$E_{cell} = 0 - \frac{0.0591}{1} \log \frac{0.01}{0.1}$$E_{cell} = -0.0591 	imes \log(0.1)$$E_{cell} = -0.0591 	imes (-1) = 0.0591 \ V \approx 0.059 \ V$.

The initial $EMF$ of the concentration cell shown in the figure at $298 \ K$ is .............. $V$.

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