Iodine reacts with concentrated HNO_3 to yiel | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The chemical reaction between iodine and concentrated nitric acid is given by: $I_2 + 10HNO_3 	o 2HIO_3 + 10NO_2 + 4H_2O$. Here,the product $Y$ i

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) The chemical reaction between iodine and concentrated nitric acid is given by: $I_2 + 10HNO_3 	o 2HIO_3 + 10NO_2 + 4H_2O$. Here,the product $Y$ is $HIO_3$ (iodic acid). To find the oxidation state of iodine $(I)$ in $HIO_3$: Let the oxidation state of $I$ be $x$. $1 + x + 3(-2) = 0$ $1 + x - 6 = 0$ $x - 5 = 0$ $x = +5$. Thus,the oxidation state of iodine in $Y$ is $+5$.

Iodine reacts with concentrated $HNO_3$ to yield $Y$ along with other products. The oxidation state of iodine in $Y$ is

Similar Questions

Sulphur in $+3$ oxidation state is present in

The oxidation state of chlorine in $KClO_4$ is

Which of the following statements is not correct?

What is the correct order of decreasing oxidation state of iodine in the following compounds?

Arrange $ICl$,$HI$,$I_2$,and $HIO_4$ in the decreasing order of the oxidation number of iodine.

Vedclass Test Series

Exam Paper Generator

Online Exam Module