Is it true to say that the pair of equations $-x + 2y + 2 = 0$ and $\frac{1}{2}x - \frac{1}{4}y - 1 = 0$ has a unique solution? Justify your answer.

(A) Yes,it is true.
Given equations are:
$1) -x + 2y + 2 = 0$
$2) \frac{1}{2}x - \frac{1}{4}y - 1 = 0$
Comparing these with the standard form $a_1x + b_1y + c_1 = 0$ and $a_2x + b_2y + c_2 = 0$:
$a_1 = -1, b_1 = 2, c_1 = 2$
$a_2 = \frac{1}{2}, b_2 = -\frac{1}{4}, c_2 = -1$
Now,calculate the ratios:
$\frac{a_1}{a_2} = \frac{-1}{1/2} = -2$
$\frac{b_1}{b_2} = \frac{2}{-1/4} = -8$
Since $\frac{a_1}{a_2} \neq \frac{b_1}{b_2}$ (i.e.,$-2 \neq -8$),the pair of linear equations has a unique solution.