If f = {(1,2), (2,3), (3,1)},it is easy to se | vedclass

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(B) function $f: A 	o B$ is invertible if and only if it is a bijection (one-one and onto). Given $f = \{(1,2), (2,3), (3,1)\}$. The inverse function

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$f^{-1} = \{(2,1), (3,2), (1,3)\}$

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(B) function $f: A 	o B$ is invertible if and only if it is a bijection (one-one and onto). Given $f = \{(1,2), (2,3), (3,1)\}$. The inverse function $f^{-1}: B 	o A$ is obtained by interchanging the elements of the ordered pairs $(x, y)$ to $(y, x)$. Thus,$f^{-1} = \{(2,1), (3,2), (1,3)\}$. Rearranging the pairs,we get $f^{-1} = \{(1,3), (2,1), (3,2)\}$. Therefore,the correct option is $B$.

If $f = \{(1,2), (2,3), (3,1)\}$,it is easy to see that $f$ is one-one and onto. Find the inverse function $f^{-1}$.

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