It is found that for every $10^{\circ}C$ rise in temperature,the rate of the reaction doubles itself. This is mainly because

  • A
    The speed of the reactants doubles for every $10^{\circ}C$ rise in temperature.
  • B
    The fraction of the molecules forming the activated complex doubles itself.
  • C
    The concentration doubles itself.
  • D
    The collision frequency doubles itself.

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Similar Questions

The rate constants for the decomposition of acetaldehyde have been measured over the temperature range $700-1000 \ K$. The data has been analysed by plotting a $\ln \ k \ vs \ \frac{10^{3}}{T}$ graph,which gives a slope of $-18.5$. The value of activation energy for the reaction is $...... \ kJ \ mol^{-1}$. (Nearest integer) (Given: $R = 8.31 \ J \ K^{-1} \ mol^{-1}$)

The rate constant of a first-order reaction is $1.5 \times 10^7 \text{ s}^{-1}$ at $300 \text{ K}$ and $3.0 \times 10^7 \text{ s}^{-1}$ at $330 \text{ K}$. What is the activation energy $(E_a)$ for the reaction? $[R \times 2.303 = 19.15 \text{ J K}^{-1} \text{mol}^{-1}]$

Which of the following statements is incorrect?

$A$ reaction having equal activation energies for forward and reverse reaction has:

The rate constant of a chemical reaction at a very high temperature will approach:

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