It is given that $\triangle ABC \cong \triangle RPQ$. Is it true to say that $BC = QR$? Why?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(B) It is false to say that $BC = QR$.
Since $\triangle ABC \cong \triangle RPQ$,the corresponding parts of congruent triangles are equal $(CPCT)$.
By matching the vertices,we have $A \leftrightarrow R$,$B \leftrightarrow P$,and $C \leftrightarrow Q$.
Therefore,the side $BC$ corresponds to the side $PQ$.
Thus,$BC = PQ$,not $QR$.

Explore More

Similar Questions

Point $P$ lies in the interior of $\Delta ABC$. Prove that $PB + PC < AB + AC$.

In a triangle $ABC$,$D$ is the mid-point of side $AC$ such that $BD = \frac{1}{2} AC$. Show that $\angle ABC$ is a right angle.

Difficult
View Solution

Show that in a quadrilateral $ABCD$,$AB + BC + CD + DA > AC + BD$.

Difficult
View Solution

In $\Delta ABC$,$AB = 8 \text{ cm}$ and $BC = 10 \text{ cm}$. Then the perimeter of $\Delta ABC$ is less than how many centimeters?

In a right triangle,prove that the line segment joining the mid-point of the hypotenuse to the opposite vertex is half the length of the hypotenuse.

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo