It is given that $\Delta PQR \cong \Delta EDF$. Is it true to say that $PR = EF$? Give a reason for your answer.
(A) Yes,it is true that $PR = EF$.
Since $\Delta PQR \cong \Delta EDF$,the corresponding parts of congruent triangles are equal $(CPCT)$.
The vertices correspond as follows: $P \leftrightarrow E$,$Q \leftrightarrow D$,and $R \leftrightarrow F$.
Therefore,the side $PR$ corresponds to the side $EF$,which implies $PR = EF$.
Since $\Delta PQR \cong \Delta EDF$,the corresponding parts of congruent triangles are equal $(CPCT)$.
The vertices correspond as follows: $P \leftrightarrow E$,$Q \leftrightarrow D$,and $R \leftrightarrow F$.
Therefore,the side $PR$ corresponds to the side $EF$,which implies $PR = EF$.
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