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Water rises against gravity in a capillary tube when its one end is dipped into water because

Liquid $A$ rises to a height of $10 \ cm$ in a capillary tube and liquid $B$ falls to a depth of $2 \ cm$ in the same tube. The densities of $A$ and $B$ are $1 \ g/cm^3$ and $10 \ g/cm^3$ respectively. The contact angles of $A$ and $B$ with the tube are $0^{\circ}$ and $135^{\circ}$ respectively. If the surface tensions of $A$ and $B$ are $S_A$ and $S_B$, then the ratio $\frac{S_B}{S_A}$ is:

$A$ capillary tube,when immersed vertically in a liquid,records a rise of $3 \, cm$. If the tube is immersed in the liquid at an angle of ${60^\circ}$ with the vertical,what is the length of the liquid column along the tube in $cm$?

Water rises up to a height $h$ in a capillary tube immersed vertically in water. When this whole arrangement is taken to a depth $d$ in a mine,the water level rises up to a height $h^{\prime}$. If $R$ is the radius of the earth,then the ratio $\frac{h}{h^{\prime}}$ is

If the liquid level falls in a capillary tube,then the radius of the capillary will: